Optimal. Leaf size=282 \[ -\frac{21 b^{5/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{20 a^{11/4} \sqrt{a+b x^4}}-\frac{21 b^{3/2} x \sqrt{a+b x^4}}{10 a^3 \left (\sqrt{a}+\sqrt{b} x^2\right )}+\frac{21 b^{5/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{10 a^{11/4} \sqrt{a+b x^4}}+\frac{21 b \sqrt{a+b x^4}}{10 a^3 x}-\frac{7 \sqrt{a+b x^4}}{10 a^2 x^5}+\frac{1}{2 a x^5 \sqrt{a+b x^4}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.115697, antiderivative size = 282, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {290, 325, 305, 220, 1196} \[ -\frac{21 b^{3/2} x \sqrt{a+b x^4}}{10 a^3 \left (\sqrt{a}+\sqrt{b} x^2\right )}-\frac{21 b^{5/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{20 a^{11/4} \sqrt{a+b x^4}}+\frac{21 b^{5/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{10 a^{11/4} \sqrt{a+b x^4}}+\frac{21 b \sqrt{a+b x^4}}{10 a^3 x}-\frac{7 \sqrt{a+b x^4}}{10 a^2 x^5}+\frac{1}{2 a x^5 \sqrt{a+b x^4}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 290
Rule 325
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{1}{x^6 \left (a+b x^4\right )^{3/2}} \, dx &=\frac{1}{2 a x^5 \sqrt{a+b x^4}}+\frac{7 \int \frac{1}{x^6 \sqrt{a+b x^4}} \, dx}{2 a}\\ &=\frac{1}{2 a x^5 \sqrt{a+b x^4}}-\frac{7 \sqrt{a+b x^4}}{10 a^2 x^5}-\frac{(21 b) \int \frac{1}{x^2 \sqrt{a+b x^4}} \, dx}{10 a^2}\\ &=\frac{1}{2 a x^5 \sqrt{a+b x^4}}-\frac{7 \sqrt{a+b x^4}}{10 a^2 x^5}+\frac{21 b \sqrt{a+b x^4}}{10 a^3 x}-\frac{\left (21 b^2\right ) \int \frac{x^2}{\sqrt{a+b x^4}} \, dx}{10 a^3}\\ &=\frac{1}{2 a x^5 \sqrt{a+b x^4}}-\frac{7 \sqrt{a+b x^4}}{10 a^2 x^5}+\frac{21 b \sqrt{a+b x^4}}{10 a^3 x}-\frac{\left (21 b^{3/2}\right ) \int \frac{1}{\sqrt{a+b x^4}} \, dx}{10 a^{5/2}}+\frac{\left (21 b^{3/2}\right ) \int \frac{1-\frac{\sqrt{b} x^2}{\sqrt{a}}}{\sqrt{a+b x^4}} \, dx}{10 a^{5/2}}\\ &=\frac{1}{2 a x^5 \sqrt{a+b x^4}}-\frac{7 \sqrt{a+b x^4}}{10 a^2 x^5}+\frac{21 b \sqrt{a+b x^4}}{10 a^3 x}-\frac{21 b^{3/2} x \sqrt{a+b x^4}}{10 a^3 \left (\sqrt{a}+\sqrt{b} x^2\right )}+\frac{21 b^{5/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{10 a^{11/4} \sqrt{a+b x^4}}-\frac{21 b^{5/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{20 a^{11/4} \sqrt{a+b x^4}}\\ \end{align*}
Mathematica [C] time = 0.0093364, size = 54, normalized size = 0.19 \[ -\frac{\sqrt{\frac{b x^4}{a}+1} \, _2F_1\left (-\frac{5}{4},\frac{3}{2};-\frac{1}{4};-\frac{b x^4}{a}\right )}{5 a x^5 \sqrt{a+b x^4}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [C] time = 0.015, size = 157, normalized size = 0.6 \begin{align*} -{\frac{1}{5\,{x}^{5}{a}^{2}}\sqrt{b{x}^{4}+a}}+{\frac{8\,b}{5\,{a}^{3}x}\sqrt{b{x}^{4}+a}}+{\frac{{b}^{2}{x}^{3}}{2\,{a}^{3}}{\frac{1}{\sqrt{ \left ({x}^{4}+{\frac{a}{b}} \right ) b}}}}-{{\frac{21\,i}{10}}{b}^{{\frac{3}{2}}}\sqrt{1-{i{x}^{2}\sqrt{b}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{b}{\frac{1}{\sqrt{a}}}}} \left ({\it EllipticF} \left ( x\sqrt{{i\sqrt{b}{\frac{1}{\sqrt{a}}}}},i \right ) -{\it EllipticE} \left ( x\sqrt{{i\sqrt{b}{\frac{1}{\sqrt{a}}}}},i \right ) \right ){a}^{-{\frac{5}{2}}}{\frac{1}{\sqrt{{i\sqrt{b}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{b{x}^{4}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{4} + a\right )}^{\frac{3}{2}} x^{6}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b x^{4} + a}}{b^{2} x^{14} + 2 \, a b x^{10} + a^{2} x^{6}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [C] time = 1.67975, size = 44, normalized size = 0.16 \begin{align*} \frac{\Gamma \left (- \frac{5}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{5}{4}, \frac{3}{2} \\ - \frac{1}{4} \end{matrix}\middle |{\frac{b x^{4} e^{i \pi }}{a}} \right )}}{4 a^{\frac{3}{2}} x^{5} \Gamma \left (- \frac{1}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{4} + a\right )}^{\frac{3}{2}} x^{6}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]